ext_114596 ([identity profile] cobaltnine.livejournal.com) wrote in [personal profile] kleenexwoman 2008-07-04 01:56 am (UTC)

He's going to have left-over Smirnoff.

For percentage problems, you have to pretend all you're making is a 1 unit thing. In this case, a 1-unit thing is called '1 drink'. Now, instead of having the volume of the drink be x - which is what I instinctively want to do - remember you just have 1. Thus the drink is made up of x units of vanilla vodka and 1-x units of Smirnoff. Your total will be 1 unit of Drink. This can later be converted into actual units, because 1-x and x will give you proportions.

Ditch the percent signs, but remember you want 1 unit of Drink at 40%. This is your goal percent.

35x = 35% alcohol, amount therein in Drink
50(1-x) = 50% alcohol, amount therein in Drink
1 = unit of Drink but 40% = amount of alcohol in drink

35x + 50(1-x) = 40
Solve for x and you get x = 2/3
2/3 of the drink is vanilla vodka, and 1/3 is Smirnoff.

Given the average drink is about 36 mL alcohol, you end up with 24 mL vanilla and 12 mL plain, with a 40% alcohol content and you are on the floor.

Without the volume of the bottles, I cannot tell how drunk Illya may get, but the answer is presumably 'really', unless given airplane bottles.

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